Math, asked by vishishtmishra1, 10 months ago


if \:  \sin(a)  \:  +  \:  \cos(a) \:  =  \:  \sqrt{2 }cos(a) \:  then \: the \: value \: of \:  \tan(a)  \: is \\  \\ (a) \:  \sqrt{2}  - 1 \\ (b)  \: \sqrt{2}  + 1 \\ (c) \:  \sqrt{2}  \\ (d) \:  -  \sqrt{2}

Answers

Answered by saumya983
3

Answer:

Hey,

There your answer

Since \:  \\  \:  \:  \:  \: \:  \:  \: TanA =  \frac{sina}{cosa}  \\  \:  \:  => SinA = TanA \times CosA \\  \\ Now \\  \:  \:  \: A/q \\  \:  \:  \:  \: SinA \: + CosA =  \sqrt{2} CosA \\  => TanA.CosA +  CosA=  \sqrt{2} CosA \\  => CosA(TanA + 1) =  \sqrt{2} CosA \\  => TanA + 1 =   \sqrt{2}  \\  =>  TanA=  \sqrt{2}  - 1

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