Math, asked by AdorableStuti, 10 months ago

$if \: \sqrt{2 } = 1.414 \: \sqrt{5} \\ 2.236 \: and \: \sqrt{3} = 1.732 \: \: find \\ the \: value \: of: \: \: \sqrt{72} + \: \sqrt{48}$
please give me correct answer please

Answers

Answered by brainlyaryan12

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$\Large{\sqrt{72}+\sqrt{48}}$

This could also be written as -

$\sqrt{2×2×2×3×3}+\sqrt{2×2×2×2×3}$

⚡ $\large{6\sqrt{2}+4\sqrt{3}}$ ⚡

Given-

⭐ $\sqrt{2}=1.414$

⭐ $\sqrt{3}=1.732$

⬆️⬆️Using these value in the question-

➡️ $6\sqrt{2}+4\sqrt{3}$

➡️ $6×\blue{1.414}+4×\blue{1.732}$

➡️ $\large{8.484+6.928}$

➡️⭐ $\huge\orange{\fbox{\pink{15.412}}}$ ⭐⬅️

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