Question

$if \tan \: a \: = \: 1 \: and \: \tan \: b \: = \: \sqrt{3} \: then \: find \: the \: value \: of \: \cos \: a \: \cos \: b \: - \: sin \: a \: .sin \: b$
Please explain

Please answer it correctly

I will mark you as brainlist

Please answer it very fast

Answer 1

Answer:

(1 - √3)/(2√2)

Step-by-step explanation:

Given:

(i) tan A = 1

⇒ tan A = tan 45

⇒ A = 45

(ii) tan B = √3

⇒ tan B = tan 60°

⇒ B = 60°

Now,

cos A cos B - sinA sin B

⇒ cos(45) cos(60) - sin(45) sin(60)

⇒ (1/√2) (1/2) - (1/√2) (√3/2)

⇒ (1/2√2) - (√3/2√2)

⇒ (1 - √3)/2√2

Hope it helps!

Answer 2

$since \: \tan(a) = 1\ \: and \: \\ tan(b) = \sqrt{3} \\ we \: know \: that \: tan \: 45 = 1 \\ \: and \: tan \: 60 = \sqrt{3} \\ hence \: a = 45 \\ b = 60$can u tell me the answer of 1st question