Question

$if \: \tan( \gamma ) = a \div b \: then \: \cos( \gamma ) =$
please help me in above question​

Answer 1

Answer:

Here is the answer =>

Step-by-step explanation:

$\tan( \gamma ) = a \div b$

And Tan(Φ)=p/b

So Perpendicular =a.

And Base=b.

• And CosΦ= B/H.

And in the Δ

Base=>b

Perpendicular =>a

Hypotenuse =>?.

So h^2=b^2+p^2

h^2=b^2+a^2

h=√a^2+b^2.

So

$\cos( \gamma ) = b \div \sqrt{ {a }^{2} + {b}^{2} }$(b/h)

HOPE IT HELPS.