Math, asked by jatindevisetty, 2 months ago


if \tan(theta )  +  \sec(theta)  =  \frac{2}{3} then \:  \tan(theta)  -  \sec(theta)

Answers

Answered by Anonymous
2

this is your answer.

Hope this will help you more

Attachments:
Answered by kanishkagupta1234
2

or,cot theta=1/tan theta=1/3/4=4/3

or,cot^2theta=16/9

Now, sin theta=(1/cosec^2 theta)^1/2

=[1/(1+cot^2 theta)]^1/2

So,sin theta=[1/(1+16/9)]^1/2

=[1/(16+9)/9]^1/2

=(9/25)^1/2

or,sin theta=3/5

Again, sec theta=1/cos theta

or,sec theta=[1/(1-sin^2 theta)]^1/2

or,sec theta=[1/(1-9/25)]^1/2

or, sec theta=[25/(25-9)]^1/2

or, sec theta=(25/16)^1/2

or, sec theta=5/4

Ans: sin theta=3/5 & sec theta=5/4

5.5K views

Related Questions (More Answers Below)

If , can you find ?

9,139 Views

If tan theta = 3/4, then what will the value of sin theta be?

2,938 Views

If tan theta=m-(1) /(4m), then what is the value of sec theta?

472 Views

If tan A=-4/3, then what is sin A=?

379 Views

If sin A = 3/4, then cos A and tan A are equal to what?

23,758 Views

Profile photo for Ved Prakash Sharma

Ved Prakash Sharma, former Lecturer at Sbm Inter College, Rishikesh (1971-2007)

Answered 2 years ago · Author has 9.3K answers and 6.1M answer views

Let theta = x

tan x=3/4. , sin x=? and. sec x=?

sec^2x=1+tan^2x=1+9/16= 25/16

sec x=+/-(5/4). Answer

cos x= +/- 4/5

sin x=+/-√(1-cos^2x) = +/- √(1–16/25)=+/- √(9/25) = +/-3/5. Answer.

Second-method:-

tan x= 3/4

or. sin x/cos x= 3/4

or. (sin x)/3= (cos x)/4 =k(led)

or. sin x= 3k. , cos x=4k

sin^2x+cos^2x=1. =>. 9k^2+16k^2=1. or. 25k^2 = 1

k = +/-1/5

sin x= 3k = +/-3/5. Answer

and. cos x=4k = +/-(4/5). or sec x= +/-(5/4). Answer.

Similar questions