Question

$if the sum of the squares of the roots of {x}^{2} + px - 3 = 0 is \: 10 then p =$
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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Given a ^2 +b ^2=10

Sum of the roots ⇒a+b=−p

Product of the roots ⇒ab=−3

a ^2+b^2 =(a+b) ^2 −2ab

⇒10=(−p) ^2−2(−3)

⇒10=p^2 +6

⇒p^2 =4

⇒p=±2