Question

$if \: theta \: is \: n \: actue \: an \: actue \: angle \: and \: \tan(theta) + \cot(theta) = 2 \: find \: the \: value \: of \: \tan^12 \: theta + \cot^12 \: theta$
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Answer 1

Given that : tanA + cotA = 2

then, A = 45°

tan45° = 1 and cot45° = 1

The acute angle will be 45°

Then,

${ \tan }^{12} 45 + { \cot }^{12} 45 \\ \\ = > {(1)}^{12} + {(1)}^{12} \\ \\ = > 1 + 1 = 2$

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Answer 2

Step-by-step explanation:

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