Question

$if \: {x}^{2} + \frac{1}{x {2}^{} } = 18 \: then \: find \: the \: value \: of \: x - \frac{1}{x}$
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Answer 1

Answer:

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Step-by-step explanation:

tex]if \: {x}^{2} + \frac{1}{x {2}^{} } = 18 \: then \: find \: the \: value \: of \: x - \frac{1}{x} [/tex]

Answer 2

x-1/x=4

As we know that x2 + 1/x2 = 18.

So x-1/x=

When subtracting 2 from both sides, we get

x2 + 1/x2 – 2 × x × 1/x = 18 – 2

(x – 1/x)2 = 16

x – 1/x = √16

x – 1/x = 4