Question

$if \: {x}^{2} + \frac{1}{x {}^{2} } = 27 \: then \: find \: the \: value \: of \: each \\ 1. \: x + \frac{1}{x } \\ 2. \: x - \frac{1}{x}$
if u ans i would put as brainlist

Answer 1

Given Equation is x^2 + 1/x^2 = 27

It can be written as:

= > x^2 + 1/x^2 - 2 = 25

= > (x - 1/x)^2 = 25

= > (x - 1/x) = 5.


Therefore the value of x - 1/x = 5.

Now,

= > x^2 + 1/x^2 = 27

= > x^2 + 1/x^2 + 2 = 29

= > (x + 1/x)^2 = 29

$= \ \textgreater \ x + \frac{1}{x} = \sqrt{29}$


Hope this helps!

Answer 2

Hey,
Thanks for asking this question.

Please refer to the file that I have attached, in which I have solved both parts of the question, step by step.

Hope My Answer Helped.