Question

$if \: {x}^{2} + \frac{1}{x {}^{2} } = 6 \: find \: the \: value \: of \: x { { }^{2} }^{2} + \frac{1}{x { {}^{2} }^{2} }$

Answer 1

Heya!✋

Here is your answer.

=================================

Given that,

x²+1\x²=6

The given equation,
( x²)²+ 1\(x²)²
=> (x²+1\x²)²-2×x²×1\x² [a²+b²=(a+b)²-2ab]
=> (6)²- 2
=> 36-2
=> 34
[Answer]

==================================

Friend, I hope that you can solve such type of math.