Math, asked by koteswararao9, 7 months ago


if \:  {x}^{2}  +  {y}^{2}  = 11xy  \: then \:  \\ prove \: that  \\ \: 2 log \: (x - y) = 2 log3 +  logx +  logy
prove that

Answers

Answered by Yaminii2006
0

Velocity of the motor car is 36 km/h

Option (3)

__________________________

\orange{\bigstar}★ Given \green{\bigstar}★

Mass of the motor car is 800 kg

It's Kinetic energy is 40,000 Joules

\orange{\bigstar}★ To Find \green{\bigstar}★

Velocity of the motor car

\orange{\bigstar}★ Key Points \green{\bigstar}★

\pink{\bigstar}\ \; \bf K.E=\dfrac{1}{2}mv^2★ K.E=

2

1

mv

2

\begin{lgathered}\rm 1\ km/h=\dfrac{5}{18}\ m/s\\\\\pink{\bigstar}\ \; \bf 1\ m/s=\dfrac{18}{5}\ km/h\end{lgathered}

1 km/h=

18

5

m/s

★ 1 m/s=

5

18

km/h

\orange{\bigstar}★ Solution \green{\bigstar}★

Mass , m = 800 kg

Kinetic energy , KE = 40,000 J

Velocity , v = ? km/h

Apply formula ,

\begin{lgathered}\bf K.E=\dfrac{1}{2}mv^2\\\\\to \rm 40,000=\dfrac{1}{2}(800)v^2\\\\\to \rm 40,000=400v^2\\\\\to \rm 400=4v^2\\\\\to \rm 4v^2=400\\\\\to \rm v^2=100\\\\\to \bf v=10\ m/s\ \; \pink{\bigstar}\end{lgathered}

K.E=

2

1

mv

2

→40,000=

2

1

(800)v

2

→40,000=400v

2

→400=4v

2

→4v

2

=400

→v

2

=100

→v=10 m/s ★

But final answer is in km/h , So ,

\begin{lgathered}\to \rm v=10\times \dfrac{18}{5}\ km/h\\\\\to \rm v=2\times 18\ km/h\\\\\to \bf v=36\ km/h\ \pink{\bigstar}\end{lgathered}

→v=10×

5

18

km/h

→v=2×18 km/h

→v=36 km/h ★

So , Option (3) is correct

__________________________

Answered by VarunGuleria
3

Answer:

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