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hope this helps you.
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Answered by
1
Hi ,
x^-2 - y³ = 3
( 1/x² )- y³ = 3
( 1 - x²y³ ) / x² = 3
1 - x²y³ = 3x²
1 = 3x² + x² y³
Therefore ,
3x² + x²y³ = 1
Hence proved.
I hope this helps you.
:)
x^-2 - y³ = 3
( 1/x² )- y³ = 3
( 1 - x²y³ ) / x² = 3
1 - x²y³ = 3x²
1 = 3x² + x² y³
Therefore ,
3x² + x²y³ = 1
Hence proved.
I hope this helps you.
:)
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