Question

$if \: x = {y}^{ \frac{2}{3} } and \: y = {z}^{ - 2} then \:$
find the value of x in terms of z​

Answer 1

$\huge\mathcal{\fcolorbox{aqua}{azure}{\blue{♡Answer★}}}$

From the question, We can say that,

x = (3y)/4, and z = (4y)/3 , and y = y,

$\rm{\dfrac{x+y+z}{3z} = \dfrac{ \dfrac{3y}{4} +y + \frac{4y}{3} }{4y} }$

• => (9y + 12y + 16y)/48y,
• => 37y/48y , Cancelling out the y variable,
• => 37/48,

• Therefore the answer is 37/48,

_______________________________________

Answer 2

Given 3−2

2

Given eq x+

x

1

=

x

x

2

+1

...1

now put the value of x in eq 1

⇒

3−2

2

(3−2

2

)

2

+1

⇒

3−2

2

9−12

2

+8+1

⇒

3−2

2

18−12

2

⇒

3−2

2

6(3−2

2

)

=6