Question

$in \: quadratic \: equation \: x {}^{2} - 4x + k = 0 \: has \: real \: and \: equal \: roots \: then \: find \: k \:$
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Answer 1

Answer:

${b}^{2} - 4ac = 0 \\ { (- 4)}^{2} - 4(1)(k) = 0 \\ 16 - 4k = 0 \\ 16 = 4k \\ k = 16 \div 4 \\ k = 4$

Answer 2

gaaa.nd fttt gyi .xD

to nashihtttt dene aa gyi

tum rand.iyo ka yahi kaam hai re .