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Step-by-step explanation:
In ∆ABC and ∆ABD,
AC = AD (Given)
AB = AB (Common side)
∠DAB = ∠BAC (AB bisects ∠A)
therefore, ∆ABC ≅ ∆ABD (by S.A.S Criteria)
hence, proved!
BC = BD (by C.P.C.T)
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