Science, asked by thapaavinitika6765, 8 months ago

\int _0^{\pi }\sin \left(x\right)dx+\theta

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Answered by Anonymous
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Answered by Anonymous
1

\int _0^{\pi }\sin \left(x\right)dx+\theta

\rule{250}{6}

\int _0^{\pi }\sin \left(x\right)dx+θ=2+θ

\int _0^{\pi }\sin \left(x\right)dx=2

\mathrm{Use\:the\:common\:integral}:\quad \int \sin \left(x\right)dx=-\cos \left(x\right)

=\left[-\cos \left(x\right)\right]^{\pi }_0

\mathrm{Compute\:the\:boundaries}:\quad \left[-\cos \left(x\right)\right]^{\pi }_0=2

=2+θ

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