Question

$\int\frac{1}{2}dx - { \int\frac{1}{2}dx}$​

Answer 1

Answer:

Q.

$\int\frac{1}{2}dx - { \int\frac{1}{2}dx}$

Answer:-

• Integrating with respect to dx
• integration of adx is 'ax' where 'a' is constant

$\int\frac{1x}{2}+C- { \int\frac{1x}{2}+C}=0$

• 1/2 is a constant term in given question
• C is the constant of integration/anti derivative

Formula used

$a\int{dx} =ax$

Answer 2

Answer:

$\large\bold\red{0}$

Step-by-step explanation:

To find the value of,

$\int \frac{1}{2} dx - \int \frac{1}{2} dx$

Further simplifying,

We get,

$= \frac{1}{2} \int \: dx - \frac{1}{2} \int \: dx$

Now,

We know that,

$\bold{\int \: dx \: = x}$

Therefore,

Putting the values,

We get,

$= \frac{x}{2} - \frac{x}{2} \\ \\ = 0$

Hence,

• 0 is the required answer.

Some extra information :-

• $\int {x}^{n} dx= \frac{ {x}^{n + 1} }{n + 1}$

• $\int \sin(x) dx = - \cos(x)$

• $\int \cos(x) dx = \sin(x)$

• $\int {a}^{x} dx= \frac{ {a}^{x} }{ ln(a) }$