![\int\frac{dx}{\sqrt{2ax-x^2} } = a^n sin^{-1}[\frac{x}{a}-1] \int\frac{dx}{\sqrt{2ax-x^2} } = a^n sin^{-1}[\frac{x}{a}-1]](https://tex.z-dn.net/?f=%5Cint%5Cfrac%7Bdx%7D%7B%5Csqrt%7B2ax-x%5E2%7D+%7D+%3D+a%5En+sin%5E%7B-1%7D%5B%5Cfrac%7Bx%7D%7Ba%7D-1%5D)
The value of n is
A) 0
B) -1
C) 1
D) None of these
Also please explain your answer then only I will mark you brainliest
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Answer:
Bro the will be
Value of n is - 1
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