Question

$\int\limits {cos6x} .\, dx$

Answer 1

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let I = \int\limits \frac{ x + cos6x }{3 x^{2} + sin 6x} dx

let 3 x^{2} + sin 6x = t

(6x+6cos 6x) dx = dt

(x + cos 6x) dx = dt/6

I = \frac{1}{6} \int\limits \frac{dt}{t}

= \frac{1}{6} log |t| +c

= \frac{1}{6} log |3 x^{2} + sin 6x| + c

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Answer 2

Answer. 1/6 sin(6x) + C

Hope it helps you

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