Question

$is \: the \: oxidation \: state \: of \: sulphur \: in \: {so4}^{2 -} \: is \: + 4$
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Answer 1

Answer:

Oxidation state of sulphur in (SO4)-² is +6

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Answer 2

Answer:

+6

Explanation:

as you know that oxidation state of a neutral compound say CO2 will be

sum of both = 0

i:e oxi state of O + oxidation state of C=0

but oxidation state of an ion will be equal to the whole charge on ion which in this case(SO4(2−)) is -2

so,

oxidation state of S + 4( oxd state of O) = -2

oxidation state of S+ 4(-2) = -2......( each oxygen has -2 oxidation state)

oxidation state of S + (-8) = -2

oxidation state of S  = 8 -2

oxidation state of S = +6

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