Math, asked by mrfaisu007, 3 months ago

$|kaise \: laga \: |$
ABCD is a parallelogram such that AB = 2 AD
E is the midpoint of (AB) and F is the midpoint of [CD]
1) Prove that AEFD and BCFE are rhombuses.
2) Prove that triangle AFB is a right triangle.
HELP

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Answers

Answered by XxMissBrainlyxX

Let us draw a parallelogram ABCD Where F is the midpoint Of side DC of parallelogram ABCDTo prove : AEFD is a parallelogramProof Therefore ABCDAB || DCBC || ADAB || DC21AB=21DCAE = DFAlso AD || EFTherefore ,AEFC is a parallelogram.

Step-by-step explanation:

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ABCD is a parallelogram such that AB = 2 ADE is the midpoint of (AB) and F is the midpoint of [CD]1) Prove that AEFD and BCFE are rhombuses.2) Prove that triangle AFB is a right triangle. HELP ​​

Answers

$|kaise \: laga \: |$
ABCD is a parallelogram such that AB = 2 AD
E is the midpoint of (AB) and F is the midpoint of [CD]
1) Prove that AEFD and BCFE are rhombuses.
2) Prove that triangle AFB is a right triangle.
HELP