Math, asked by mrfaisu007, 4 months ago

$|kaise \: laga \: |$
ABCD is a parallelogram such that AB = 2 AD
E is the midpoint of (AB) and F is the midpoint of [CD]
1) Prove that AEFD and BCFE are rhombuses.
2) Prove that triangle AFB is a right triangle.
HELP

Attachments:

sneha8617: subh raatri

mrfaisu007: gn

sneha8617: neend hi nahi aa rahi

sneha8617: bro

mrfaisu007: ohhh

mrfaisu007: lekin mujhe to rahi hai

mrfaisu007: byee

sneha8617: ok bye

sneha8617: gn

mrfaisu007: gn siso

Answers

Answered by XxMissBrainlyxX

Let us draw a parallelogram ABCD Where F is the midpoint Of side DC of parallelogram ABCDTo prove : AEFD is a parallelogramProof Therefore ABCDAB || DCBC || ADAB || DC21AB=21DCAE = DFAlso AD || EFTherefore ,AEFC is a parallelogram.

Step-by-step explanation:

mrfaisu007: btw mera A hai (✷‿✷)

XxMissBrainlyxX: aapka naam kya hai

mrfaisu007: Prathamesh

XxMissBrainlyxX: aacha hmm u r right ✅

mrfaisu007: ;)

XxMissBrainlyxX: acha chlo bye good night

mrfaisu007: Bye

mrfaisu007: good night (◔‿◔)

sneha8617: subh raatri

XxMissBrainlyxX: aapko bhi

Previous Question

Next Question

ABCD is a parallelogram such that AB = 2 ADE is the midpoint of (AB) and F is the midpoint of [CD]1) Prove that AEFD and BCFE are rhombuses.2) Prove that triangle AFB is a right triangle. HELP ​​

Answers

$|kaise \: laga \: |$
ABCD is a parallelogram such that AB = 2 AD
E is the midpoint of (AB) and F is the midpoint of [CD]
1) Prove that AEFD and BCFE are rhombuses.
2) Prove that triangle AFB is a right triangle.
HELP