Chemistry, asked by parineetasakshi5847, 1 year ago

\Lambda^o_{m(NH_4OH)} is equal to ....... .
(a) \Lambda^o_{m(NH_4OH)} + \Lambda^o_{m(NH_4Cl)} - \Lambda^o_{m(HCl)}
(b) \Lambda^o_{m(NH_4Cl)} + \Lambda^o_{m(NaOH)} - \Lambda^o_{m(NCl)}
(c) \Lambda^o_{m(NH_4Cl)} + \Lambda^o_{m(NaCl)} - \Lambda^o_{m(NaOH)}
(d) \Lambda^o_{m(NaOH)} + \Lambda^o_{m(NaCl)} - \Lambda^o_{m(NH_4Cl)}

Answers

Answered by kritarth24
0

b option is answer.....

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