Question

$\large\bf{Question : - }$

Find ​Area of the Rectangle whose sides are :- 3 cm and 4 cm .

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Answer 1

Question :-

➻ Find Area of the Rectangle :-

• Lenght is 3 cm .
• Breadth is 4 cm .

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Answer :-

• Area of Rectangle is 12 cm² .

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Explanation :-

• Here, Lenght of Rectangle is given 3 cm . Breadth of Rectangle is 4 cm . And, we have to calculate the Area of Rectangle .

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➻ Formula Required :-

• $\sf{Area \: of \: Rectangle = L \times B}$

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➻ Where ,

• L denotes to the Lenght .
• B denotes to the Breadth .

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➻ By substituting the given values :-

$\dag \: \: \sf{ Area \: _{Rectangle} = Lenght \times Breadth}$

$\Longrightarrow \: \: \sf{Area \: _{Rectangle} \: = \: 3 \: \times \: 4}$

$\Longrightarrow \: \: \sf{Area \: _{Rectangle} \: = \: 12 \: {cm}^{2} }$

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Hence :-

• Area = 12 cm² .

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$\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \pmb {\sf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Square = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \sf{Area \: of \: Rectangle = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Triangle = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Parallelogram = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Trapezium = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \sf {Area \: of \: Rhombus = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered}$

Answer 2

Answer:

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➜ Given:-

• Length of a Rectangle = 3cm
• Breadth of a Rectangle = 4cm

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➜ To Find:-

• Area of a Rectangle = ?

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➜ Using Formula:-

• Area of a Rectangle = Length × Breadth

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➜ Calculation:-

• Area of a Rectangle = Length × Breadth

⭑Substituting values in the Formula:->

Area of a Rectangle = 3cm × 4cm

➠ 12cm²

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➳ Final Answer-:

⭑ Area of a Rectangle = 12cm²

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