Prove that the circle drawn , with any side of a rhombus as diameter, passes through the point of intersection of its diagonals.
Answers
Answered by
5
Answer:
me apne acc par ja rahi hu agr apko apni maseera di yaad hai to mujhe unblock kar dena mujhe kuch baat karni hai apse
Answered by
148
Answer:
Let us consider rhombus ABCD with the two diagonals as AC and BD. Consider O as the point of intersection of diagonals.
Diagonals of a rhombus bisect each other at right angles.
AB=DC
⇒
2
1
AB=
2
1
DC
AM=DN (M and N are mid-points of AB and CD)
Similarly, AX=OM
⇒AN=ON=NB
A circle drawn with N as centre and radius AN passes through A,O and B.
Circle obtained is the required circle.
hii biograhy achhi hai pal one mistke hai sabhi ladk me mai aisi nahi hu
Similar questions