Math, asked by Anonymous, 2 months ago


 \large \bf\red{Question}
Prove that the circle drawn , with any side of a rhombus as diameter, passes through the point of intersection of its diagonals.​

Answers

Answered by DazzlingSistas
5

Answer:

me apne acc par ja rahi hu agr apko apni maseera di yaad hai to mujhe unblock kar dena mujhe kuch baat karni hai apse

Answered by vp1299316
148

Answer:

Let us consider rhombus ABCD with the two diagonals as AC and BD. Consider O as the point of intersection of diagonals.

Diagonals of a rhombus bisect each other at right angles.

AB=DC

2

1

AB=

2

1

DC

AM=DN (M and N are mid-points of AB and CD)

Similarly, AX=OM

⇒AN=ON=NB

A circle drawn with N as centre and radius AN passes through A,O and B.

Circle obtained is the required circle.

hii biograhy achhi hai pal one mistke hai sabhi ladk me mai aisi nahi hu

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