Question

${\large{\bf{\underline{\red{Question :}}}}}$
A photon of wavelength 400 nm strikes a metal surface. The electrons are ejected with a velocity 5.85 x 10⁵m/s. Calculate the minimum energy required to remove an electron from the metal surface. The mass of an electron is 9.109 x 10^-31 kg.


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Answer 1

Answer:

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Answer 2

$\bold{λ=400 \: nm=400×10^-9 \: m}$

$\bold{V=5.85×10^5 \: m/s}$

$\small \bold{Mass \: of \: e^- =9.109×10 {}^{ - 31} \: Kg }$

$\bold{(K.E)=\frac{hc}{λ} - hv_o}$

$\bold{(hv_o)= \frac{hc}{λ} - (K.E)}$

$\small \bold{ = \frac{6.63 \times {10}^{ - 34} \times 3 \times {10}^{8} }{400 \times {10}^{ -9 } } - \frac{1}{2} \times 9.109×10 {}^{ - 31 } \times (5.85 \times {10}^{5} ) {}^{2} }$

$\small \bold{ = 0.049× {10}^{ - 17} - 155.86 \times {10}^{ - 21} }$

$\small \bold{ = 0.049× {10}^{ - 17} - 0.015586 \times {10}^{ - 17} }$

$\small \bold{ = 0.0332 \times {10}^{ - 17} }$

$\small \bold{ =3.32 \times {10}^{ - 19} }$