Question

$\large \bold \red{ \log i( {i}^{x} ) = \log i ( 2)}$

Don't spam otherwise report your answer​

Answer 1

$\bold \red{ \cancel{ \log i}( \cancel{ {i}}^{x} ) = \log i ( 2)}$

$\bold \red{x = \frac{ ln(2) }{ ln(i) } }$

$\bold \red{= \frac{ ln(2) }{ \cancel{ ln}( \cancel{ {e}}^{i \frac{\pi}{2} } ) } }$

$\bold \red{ = \frac{i \cdot ln(2) \cdot2 }{i \cdot i \cdot\frac{\pi}{ \cancel2} \cdot \cancel2 } }$

$\bold \red{= \frac{ - 2i \: ln(2) }{ \pi} }$

Answer 2

Answer:

$\bold \green{ \cancel{ \log i}( \cancel{ {i}}^{x} ) = \log i ( 2)}$

$\bold \purple{x = \frac{ ln(2) }{ ln(i) } }$

$\bold \blue{= \frac{ ln(2) }{ \cancel{ ln}( \cancel{ {e}}^{i \frac{\pi}{2} } ) } }$

$\bold \red{ = \frac{i \cdot ln(2) \cdot2 }{i \cdot i \cdot\frac{\pi}{ \cancel2} \cdot \cancel2 } }$

$\bold \red{= \frac{ - 2i \: ln(2) }{ \pi} }$