Question

$\large\bold{\underline{\underline{Question:-}}}$

A 100uF capacitor in Series with a 40$\ampere$ resistence is connected to a 110V,60 HZ supply.

a). What is the maximum current in the circuit?

b). What is the time lag between the current maximum and the voltage maximum.​

Answer 1

Answer:

a) That maximum current is equal to 28.2885 volts divided by 9.936 ohms. That value is equal to 2.847 amps. That's the maximum current in this circuit.

b) Φ = Phase difference between voltage and current At time, t = 0. Hence, the time lag between the maximum voltage and the maximum current is 3.2 ms.

Answer 2

$\large\bold{\underline{\underline{Answers:-}}}$

a) That maximum current is equal to 28.2885 volts divided by 9.936 ohms. That value is equal to 2.847 amps. That's the maximum current in this circuit.

b) 0= Phase difference between voltage and current At time, t = 0. Hence, the time lag between the maximum voltage and the maximum current is 3.2 ms.