Question

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A playground has the shape of a rectangle, with two semi-circles on its smaller sides as diameters, added to its outside. If the sides of the rectangle are 36 m and 24.5 m, find the area of the playground. (Take π = $\frac{22}{7}$).

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Answer 1

$\sf\orange{GIVEN\:: }$

• Length of the rectangle = 36 m
• Breadth of the rectangle = 24.5 m
• Diameter of the Semi-Circle = 24.5 m
• Radius = $\frac{24.5}{2}$

Area of the Playground = Area of Rectangle + 2 × Area of one Semi-Circle

⟶ Area of Rectangle = l × b = 36 × 24.5 = 882 m²

⟶ Area of 2 Semi-Circles = $\frac{1}{2}$ × 2 × π × r²

= πr²

= $\frac{22}{7}$ × $\frac{24.5}{2}$ × $\frac{24.5}{2}$

= 471.625 m²

Area of Playground = 882 + 471.625 = 1,353.625 m²

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Answer 2

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$\large\sf\red{✧Given:}$

Radius of the semicircle,r=$\sf \frac{24.5}{2}$=12.25.

It is given that the playground has a shape of a rectangle, with two semicircles on its smaller sides as diameter, added to its outside. So,Area of the playground = Area of rectangle + 2 × Area of semi-circle

$\sf{=36×24.5+2×π× \frac{12.25^{2}}{2}} \\ \sf{=882+471.625= \blue{1353.625 m^{2} }}$

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