Question

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Prove that 3 = 4

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Answer 1

Answer:

1)*TO PROVE 1=2

Let a and b were 2 nonzero integers where a=b

a=b

multiply both sides by a

a^2 = ab

subtract b^2 from both sides

a^2-b^2 = ab-b^2

(a+b)(a-b) = b(a-b) since (a+b)(a-b) = a^2-b^2

dividing both sides by(a-b)

a+b=b

but we know a=b

a+a=a

2a=a

dividing both sides by a

2=1

or

1=2 hence proved

*2)*To prove 2=3

Let a,b and c were 3 nonzero integers

a = 3a-2a

3a-2a = a

let a=b+c

3a-2a = 3(b+c)-2(b+c)

3a-2a = 3b+3c-2b-2c

rearranging....

3a-3b-3c = 2a-2b-2c

3(a-b-c)=2(a-b-c)

dividing both sides by (a-b-c)

3=2

or

2=3 hence proved

*3)*To prove 3=4

Let a,b and c were 3 nonzero integers

let a+b = c

4a-3a+4b-3b = 4c-3c

rearranging....

4a+4b-4c = 3a+3b-3c

4(a+b-c) = 3(a+b-c)

dividing both sides by (a+b-c)

4=3

or

3=4 hence proved

All the proofs above written contain one or more than one falses

thats why the are not accepted for any science or mathematics calculations

Step-by-step explanation:

please mark as braniliest

Answer 2

Step-by-step explanation:

★Solution★

Assusme a+b+c

• 4a-3a+4b-3b=4c-3c

• 4a+4b-4c=3a+3b+3c

• 4(a+b-c)=3(a+b-c)

4=3