Math, asked by XxLUCYxX, 19 days ago


 \large \color{lime}  \:  \bigstar \: More \: Formulas \:  \\  \\  \color{aqua}Si \:  =  \:  \frac{P \times R  \times T}{100}  \\  \\  \\  \color{aqua}Amount \:  =  \: Principal\:+\:Intrest \\  \\  \\  \color{aqua}Formula \: for \: Ci \:   =  \: A\:=\:P(  {\frac{1 + r}{n} )}^{n \times t }  \\ \color{aqua}where \:  \: A =\:final\: amount \\\color{aqua} P\:=\: Principal \\ \color{aqua}r  \: = \:rate \: of \: intrest  \\ \color{aqua} n  \: =  \: number  \: of  \: times  \: interest  \: applied \:  per \:  time \:  period \\ \color{aqua}t \:  =  \: number \:  of  \: time \:  periods \:  elapsed.

Answers

Answered by itzharshu439
4

\huge\bf\underline{\underline{\pink{A}\orange{N}\blue{S}\red{W}\green{E} \purple{R}}}★

 = \: A\:=\:P( {\frac{1 + r}{n} )}^{n \times t } \\ \color{aqua}where \: \: A =\:final\: amount \\\color{aqua} P\:=\: Principal \\ \color{aqua}r \: = \:rate \: of \: intrest \\ \color{aqua} n \: = \: number \: of \: times \: interest \: applied \: per \: time \: period \\ \color{aqua}t \: = \: number \: of \: time \: periods \: elapsed.

Answered by maheshtalpada412
2

Step-by-step explanation:

\huge\mathcal\colorbox{purple}{{\color{aqua}{\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|}  \hline\bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\\hline \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3}}{2} &1 \\ \\\hline \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \hline\rm tan A & 0 & \dfrac{1}{ \sqrt{3} }&1 & \sqrt{3} & \rm \infty \\ \\\hline \rm cosec A & \rm \infty & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\\hline \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm \infty \\ \\ \hline\rm cot A & \rm \infty & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0\end{array}}} }}}

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