Γhere αre m resıstor eαch of resıstαnce R. Ғırst theч αll αre connected ın serıes αnd equıvαlent resıstαnce ıs X. Ṉoɯ theч αre connected ın pαrαllel αnd equıvαlent resıstαnce ıs Ɏ. Whαt ıs the rαtıo of X αnd Ɏ?
Answers
R1 , R2 and R3 , VAB = VR1 + VR2 + VR3 = 9V.
Using Ohm’s Law, the voltage across the individual resistors can be calculated as:
Voltage across R1 = IR1 = 1mA x 1kΩ = 1V
Voltage across R2 = IR2 = 1mA x 2kΩ = 2V
Voltage across R3 = IR3 = 1mA x 6kΩ = 6V
giving a total voltage VAB of ( 1V + 2V + 6V ) = 9V which is equal to the value of the supply voltage. Then the sum of the potential differences across the resistors is equal to the total potential difference across the combination and in our example this is 9V.
The equation given for calculating the total
You can refer to the attachment also
Answer:
As the resistors are connected together in series the same current passes through each resistor in the chain and the total resistance, RT of the circuit must be equal to the sum of all the individual resistors added together.
