Question

$\LARGE{\color{teal}{\mathtt{\mathsf{question - ⠀}}}}$
Find the sum of first 24 terms of the list of numbers whose nth term is
given by :-
a = 3 + 2n​

Answer 1

Answer:

the nth term is an-3+2n so by using this we can find the value of terms like

a1-5,a2=7,a3=9

and a24-51

now the first term is 5 and the last term

is 51 and the difference is 2

by using the formula for sum of n

terms i. e

sn =n/2(2a+(n-1)d)

so s24=24/2(10+23*2) i. e 672 ans.

❤️ Bhagyashree Happy ❤️

Answer 2

$\huge \mathbb \fcolorbox{purple}{lavender}{Answer}$

The nth term is an = 3+2n so by using this we can find the value of terms like

A1 = 5, A2 = 7, A3 = 9

and A24 = 51

Now the first term is 5 and the last term is 51 and the difference is 2.

By using the formula for sum of n terms ie,

Sn = n/2(2a+(n-1)d)

So S24 = 24/2 (10+23*2) ie. 672 Ans.