Question

$\large \colorbox{lightgreen}{ \sf{Question :}}$

A rectangular field of length 50m and breadth 45m need to be fenced. Find the cost of fencing if the changes are Rs. 4 per meter.

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Answer 1

Answer:

Fencing is done at the perimeter so, perimeter of rectangular park=2(l+b)

$= 2 \times 50 + 45m \\ \\ = 2 \times 95m \\ \\ = 190m$

Rate of fencing per meter=Rs 4

Rate of fencing 190m=190×4

=Rs 760

$\rule{190pt}{2.5pt}$

Additional information:-

• A perimeter is a closed path that encompasses, surrounds, or outlines either a two dimensional shape or a one-dimensional length.
• You can find the perimeter of any shape by adding the lengths of each side together.
• Fencing is done at the perimeter so, perimeter of rectangular park=2(l+b)=2(350+250)

Answer 2

Answer:

Given :

• A rectangular field of length 50m and breadth 45m.
• Cost of fencing is Rs.4 per meter.

To Find :

• Cost of fencing of the rectangular field.

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Solution :

As, We know that :

★ Perimeter of Rectangle = 2(L+B)

Here,

• Length = 50m
• Breadth = 45m

=⟩ 2(L+B)

=> 2( 50+45 )

=> 2( 95 )

=> 190m

Therefore, 190m will be fenced.

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★ Cost of 1m fence = Rs. 4

Cost of 190m fence = 190 × 4

=> Rs. 760

Therefore, Rs. 760 will be needed to fence the rectangular field.

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More Information:

★ Perimeter formulas ★

Triangle = Sum of All sides

Square = 4 × Sides

Circle = 2πr = πd

Rectangle = 2(L+B)