Question

$\large \displaystyle \sf \pink{ \lim_{ n \to \infty} {n}^{2} \int_{0}^{ \frac{1}{n} } {x}^{2018x + 1} \: dx}$
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Answer 1

Step-by-step explanation:

★Given

$\large \displaystyle \sf \orange{ \lim_{ n \to \infty} {n}^{2} \int_{0}^{ \frac{1}{n} } {x}^{2018x + 1} \: dx}$

★Solution

Refer To Attachment

• Hope the Attachment iz Clear.

Hope It Helps!!!

$\sf \pmb{\longmapsto} \: \ddot \smile$

Answer 2

Step-by-step explanation:

Step-by-step explanation:

★Given

$\large \displaystyle \sf \orange{ \lim_{ n \to \infty} {n}^{2} \int_{0}^{ \frac{1}{n} } {x}^{2018x + 1} \: dx}$

n→∞

lim

n

2

∫

0

n

1

x

2018x+1

dx

★Solution

Refer To Attachment

Hope the Attachment iz Clear.

Hope It Helps!!!

$\sf \pmb{\longmapsto} \: \ddot \smile$

⟼

⟼

⌣

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