Question

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If the length of the sides of a triangle ABC are 4 in, 3 in, and 5 in. Calculate its area.

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Answer 1

by heron's formula,

Area of the triangle =s(s−a)(s−b)(s−c)

We know, s = 3+4+5

= 6

∴ Area of triangle =6(6−3)(6−4)(6−5)

                              =6×3×2×1

=6cm2

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Answer 2

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Given

• AB = 4 in, BC = 3 in, AC = 5 in (let)

To find:

• Area of the triangle ABC.

Using Heron's Formula,

A = √(s(s-a)(s-b)(s-c))

As, s = (a+b+c)/2

s = (4+3+5)/2

s = 6 units

Putting the values,

A = √(6(6-4)(6-3)(6-5))

⇒ A = √(6(2)(3)(1))

⇒ A = √(36) = 6 in2

∴ The area of the triangle is 6 in²