Question

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The filament of an electric lamp draws a current of 0.4A , which lights for 3 hours . What is the charge passing in this time interval?​​

Answer 1

GIVEN

• Current = 0.4 A
• Duration of the electric bulb lights = 3 hours

TO FIND

• The amount of charge flowing through the circuit.

SOLUTION

Charge is given by Q and is calculated by the formula:

Q = I × t

Time has to calculated in seconds,

• t = 3×3600 = 10800 sec

Q = 0.4×10800 = 4320 C

• C is the Coulomb which is unit of charge.

✨Therefore, The amount of charge which flows through the circuit is found to be 4320 C

Answer 2

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GIVEN,

Current = 0.4 A

Duration of the electric bulb lights = 3 hours

TO FIND

The amount of charge flowing through the circuit.

SOLUTION

Charge is given by Q and is calculated by the formula:

Q = I × t

Time has to calculated in seconds,

t = 3×3600 = 10800 sec

Q = 0.4×10800 = 4320 C

C is the Coulomb which is unit of charge.

Therefore, The amount of charge which flows through the circuit is found to be 4320 C

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