Question

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Equivalent weight of N2 in the change N2 => NH3 is ?​

Answer 1

$\huge\green{\mid{\fbox{{คภรฬєг⤵}}\mid}}$

Hence for the given change, the equivalent weigt of N2 will be 628.

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$\huge\fbox{\red{\underline{mαrk \; mє \; вrαínlíєѕt \; plєαѕє ♥}}}$

$\large\bf{\underline\blue{❥thαnk \; чσu ♥♥}}$

Answer 2

$\pmb{ \boxed{Equivalent \: weight \: of \: N_2}} \\ \\ The \: given \: reaction \: is: \\ N_2\rightarrow NH_3 \\ \small{The \: reaction \: denoting \: electrons \: lost/gained \: : }\\ \bf \: N_2+6e^-\rightarrow 2N^{3-} \\ \sf \tiny{As \: per \: the \: above \: equation, \: the \: number \: of \: electrons \: gained \: is \: 6. }\\ \\ \cal \: Molecular \: weight \: of \: N_2 \\ = \sf 2 (Atomic \: weight \: of \: N) \\ = 2 (14) \\ = 28 \\ \\ \tt \: \scriptsize{∴ Equivalent \: weight = \frac{Molecular \: weight}{Number \: of \: e- \: lost \: or \: gained \: per \: mole} }\\ \\ \bf \: Equivalent \: weight = \frac{28}{6} = \frac{14}{3}$