The hcf of two numbers is 11 and there l.c.m is 693. if one of the numbers is 77, then the other number is
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Answer:
Product of two numbers is equls to product of LCM & HCF.
One of the number is 77,let the second number is b
LCM is 693and HCF is 11
77 X b = 693 X 11
b=99
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GIVEN
- H.C.F of the numbers = 11
- L.C.M of the numbers = 693
- One number = 77
TO FIND
- Second number
SOLUTION
We know that
HCF × LCM = Product of two numbers
⟹ 693 × 11 = 77 × y
⟹ 7623 = 77y
⟹ y = 7623/77
⟹ y = 99
∴ The second number is 99.
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