Question

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Answer 1

Answer:

Mr. Sanjeev sharma is the Chief Executive Officer (CEO) of "Gujrat Sales Limited". Production Manager of his company is going to get the repair work of a part of his factory done, on a large scale. As such, company will not be able to produce some of the products for some time. It will have to sell only those goods which are lying on stock.

Considering it, the production manager has asked the sales executives to slow down the place of sales. On the other hand, since the sales manager has set high targets of sales, he has been insisting on the sales executive to speed up the sales.

a) Which principle of management is being ignored by the company in the above paragraph?

b) Write down any one consequences of the violation of the principle mentioned in(a) above.

c) Which concept of management is being ignored by the company in this case?

please answer

Answer 2

Answer 1 -

Given -

• Initial velocity ( u ) = 30 m/s
• Final velocity ( v ) = 0
• Distance covered ( s ) = 50 m
• Mass - 1 kg

To Find -

• The force of friction between the stone and the ice

Solution -

by third equation of motion ,

${\sf{:\implies {v}^{2} = {u}^{2} + 2 as}}$

• v = 0
• u = 30
• s = 50

${\sf{:\implies {0}^{2} = {30}^{2} + 2 \times a \times 50}}$

${\sf{:\implies {0} = 900 + 2 \times (a) \times 50}}$

${\sf{:\implies - 900 = 100a}}$

${\sf{:\implies a = \dfrac{ - 900}{100} }}$

${\sf{:\implies a = - 9m/s ^{2} }}$

now acceleration is negative hence it is retardation .

Now , we know that

${\sf{:\implies F = m \times a}}$

• m = 1 kg
• a = -9

${\sf{:\implies F = 1 \times ( - 9)}}$

${\sf{:\implies F = \bold{ - 9}}}$

Here the negative sign indicates the opposing force which is Friction

__________________

Answer 2 -

Given -

• Mass (m) - 10 kg
• Height (h) - 80cm = 80/100 = 0.8m
• Acceleration (g) - 20 m/s-²

To find -

• Momentum = ?

Solution -

we know that,

${\sf{:\implies {v}^{2} = {u}^{2} + 2 gh}}$

• u = 0
• g = 20
• h = 0.8

${\sf{:\implies {v}^{2} = {0}^{2} + 2 \times 20 \times 0.8}}$

${\sf{:\implies {v} ^{2} = 32 }}$

${\sf{:\implies {v} = \sqrt{32} }}$

${\sf{:\implies v = 5.65 }}$

Now , we know that

Momentum = mass × velocity

${\sf{:\implies p = m \times v}}$

• m = 10 kg
• v = 5.65

${\sf{:\implies p = 10 \times 5.65}}$

${\sf{:\implies p = \bold{56.5}}}$