Question

$\large\mathbf{HEY\: QUESTION❤}$



If cos (A + B) = 0 and sin (A – B) = 3, then find the value of A and B where A and B are acute angles



★REQUIRED FULL EXPLANATION ANSWER​

Answer 1

Answer:

B= 90

Step-by-step explanation:

cos(A+B)= cos{90०-(A+B)}

A+B=90°-(A+B)

A+A+ B- B=90°

2A=90°

A=45°

so, B=90°

Answer 2

Step-by-step explanation:

cos(A+B)=0 and sin(A−B)=1/2

cos(A+B)=cos(90o) and sin(A−B)=sin(30o)

Since A,B are acute

or, A+B=90o.(1) and A−B=30o.(2) 

Solving from (1) and (2) we get,

A=60o and B=30o.