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zipathan939:
hello
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Step-by-step explanation:
sin^2A+cos^2A=1
Value of Tan45°=1
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[tan20°/cosec70°]²+ [cot20°/sec70°]² + 2 tan75° tan45° tan 15°.
As we know that,
We can write equation as,
→ [tan20/cosec(90° -20°)]²+ [cot20% sec(90° -20°)]²+ 2 tan75° (1) tan (90° - 75°).
→ [tan20°/sec20°]²+ [cot20°/cosec20°]² +2
tan75° cot 75°.
[sin20°/cos20°/1/cos20°]² + [cos20°/ sin 20°/1/sin20°] + 2 tan 75° X 1/tan 75°.
→ [sin²20°] + [cos²20°] +2.
→ 1 + 2.
I think that's correct :)
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