Question

$\large\mathcal{\color{maroon}{Refer\:the\: attachment♡}}$

$\small\mathcal{\underline{\color{olive}{Note:-}}}$
​


$\implies$ Solve all the questions if possible , or any two of them .

$\implies$ Pardon my handwriting , hope uh ll manage .
​

Answer 1

Answer:

$\huge \bold{ \underline{ \color{maroon}{Answer1.}}}$

Let the first part be (x) an secondly (y)

$x + y = 24(y = 24 - x)$

$7x + 5y = 146$

$7x + 5(24 - x) = 146$

$7x + 120 - 5x = 146$

$2x = 146 - 120$

$2x = 26$

$x = \frac{26}{2}$

$x = 13$

$y = 24 - x \\ y = 24 - 13 \\ y = 11$

So,the value of x=13 and y=11

$\huge \bold{ \color{aqua}{Answer2.}}$

Let the present age of Sunita be x and the present age of Sunita mother be y.

A/C to 1 st C/O

$y = 6x$

A/C to 2nd C/O

$x + 5 = \frac{1}{3} y$

put 1 in 2

$x + 5 = \frac{1}{3} \times 6x \\ 3x + 15 = 6x$

$15 = 3x$

$x = 5$

Put x=5 in eq (1)

$y = 6 \times 5 \\ y = 30$

Present ages of Sunita & Sunita's mother are 5 years and 30 years.

$\bold{ \color{goldenrod}{hope \: it \: helps \: you☺}}$

Answer 2

Question - 1 :

24 is divided into two parts.

Let the one part be x

Then the other part = (24 - x)

Given,

7 times the first part added to 5 times the second part makes 146

 7x + 5(24 - x) = 146

 7x + 120 - 5x = 146

  2x + 120 = 146

   2x = 146 - 120

   2x = 26

    x = 26/2

    x = 13

Therefore, one part = 13

the other part = 24 - 13 = 11

Question - 2 :

Let the present age of Sunita be x years

Sunita's mother's present age is six times that of Sunita's age.

Sunita's mother's present age = 6x years

After 5 years, Sunita's age = (x + 5) years

Given,

Sunita's age 5 years from now will be 1/3 rd of her mother's present age

    $\sf x+5=\frac{1}{3}(6x) \\\\ x+5=2x \\\\ 2x-x=5 \\\\ x=5$

The present age of Sunita = 5 years

The present age of her mother = 6(5) = 30 years

Question - 3 :

Let the mystery number be "x"

Given,

three more than 6 times the number is equal to 3 times the number plus 9

 6x + 3 = 3x + 9

 6x - 3x = 9 - 3

    3x = 6

    x = 6/3

    x = 2

The required number is 2.

Question - 4 :

Let the number be "x"

Given,

Kriti thinks a number and subtracts 3/2 from it, she multiplied 6 to the result obtained . the final number obtained is three times the same number she thought of.

   

=> Subtract 3/2 from the number, the result is

          $\sf x-\frac{3}{2}$

=> 6 times the result obtained is equal to 3 times the number she thought of

       $\sf 6(x-\frac{3}{2})=3x \\\\ 6(\frac{2x-3}{2})=3x \\\\ 3(2x-3)=3x \\\\ 6x-9=3x \\\\ 6x-3x=9\\\\ 3x=9 \\\\ x=9/3 \\\\ x=3$

The required number = 3