Question

$\large\mathfrak{{\pmb{\underline{\orange{Can\:someone\:please \:help}}{\orange{?}}}}}$
How many 3-digit number can be formed from the digits 0, 1, 2, 3, 4 and 5 such that the number are evèn numbers?
( I got 33 ways. Is that correct? )
$\sf\red{Thank\:you!}$​

Answer 1

Answer:

Without repetition counting the number of 3digit numbers using digits from {0,1,2,3,4,5}: Count the number of 3-digit strings whose last digit is even. This gives 60−8=52 3-digit even numbers using digits from {0,1,2,3,4,5} without repetition.

thanks