Question

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Find the sum of first 22 terms of an AP in which d = 7 and 22nd term is 149.​

Answer 1

Answer:

${\huge{\boxed{\red{\mathscr{AnSwEr}}}}}$

Given d = 7,

22nd term = 149

, ⇒ a+21d = 149

⇒a+21(7) = 149

⇒a+147 = 149

⇒a=149-147=2

${\huge{\boxed{\blue{\mathscr{Sn = \frac{n}{2} \times (2a + (n - 1) \times d)}}}}}$

S₂₂ = (22/2)(2×2+(22-1)7)

S₂₂ = 11(4+21(7))

S₂₂ = 11(4+147)

S₂₂ = 11(151)

S₂₂ = 1661.

Hence Sum of 22 terms is 1661

Answer 2

Answer:

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