Question

$\large\orange{Chemistry}$

molecular weight of a compound is 397. It contains 32.1% of O2 .find No° of O2 atom present in 1% of compound.​

Answer 1

Explanation:

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Answer 2

molecular weight of 100% compound = 397

atomic weight of oxygen in compound

= 397 × 32.1/100

now, atomic weight of 1 Oxygen = 16

so, number of oxygen atom in compound =

=> (397 × 32.1/100 × 1/16 )

==> 8 atoms of O2