Question

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Calculate the power loss (using P = I2R) in a cable with resistance 500 Ω carrying a current of 20A​

Answer 1

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★Power loss = 2,00,000 W

Given

• A cable with resistance 500 Ω carrying a current of 20A.

To find

• The power loss.

Solution

• The power loss is defined as the loss of electric charges in carrying from input to output or in supplying from one part to another.

★We know,

• The power loss = voltage × current

• P = V I

★Where

• V = voltage
• I = current
• As we learned,

★Now

• V = I R

• I = 20A
• R = 500 Ω
• ➝ 500 × 20

• ➝ 10,000 V

★So

• P = V I
• ➝ 10,000 × 20

• ➝ 2,00,000 W

Hence The power loss is 2,00,000 W

★FORMULA USED

• Voltage = Current × Resistance
• Power = Voltage × Current

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Answer 2

GIVEN

• Cable resistance 500 Ω with a current of 20A

TO FIND

• Power loss

FORMULA USED

• Voltage = Current × Resistance
• Power = Voltage × Current

CALCULATION

Power loss is known as the loss of electric charges from input to output.

NOW,

V = I R

Putting the given value, we get,

• 500 × 20
• 10,000 V

P = V I

• 10,000 × 20
• 2,00,000 W

★ Thus, the Power loss is 2,00,000 .

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