For what value of k does the quadratic equation have equal positive integer solution!?
Options: 1 , 0 , -1 or ½
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EXPLANATION.
Quadratic equation.
x² - 4kx + 4k = 0 have equal and positive.
As we know that,
⇒ D = Discriminant Or b² - 4ac.
For real and equal roots : D = 0.
⇒ b² - 4ac = 0.
⇒ (-4k)² - 4(1)(4k) = 0.
⇒ 16k² - 16k = 0.
⇒ 16k(k - 1) = 0.
⇒ k = 1 and k = 0.
MORE INFORMATION.
Nature of the roots of the quadratic expression.
(1) = Real and unequal, if b² - 4ac > 0.
(2) = Rational and different, if b² - 4ac is a perfect square.
(3) = Real and equal, if b² - 4ac = 0.
(4) = If D < 0 Roots are imaginary and unequal Or complex conjugate.
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