Question

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Using 2nd law of motion derive the relation between force and acceleration .A bullet of mass 10g strikes. sang bag at the speed of 10³ m/s-¹ and gets embedded after travelling 5m.

Calculate :
i)The resist force exerted by sand on the bullet.
ii)The time taken by bullet to come at rest.

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Answer 1

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Your Answer is in attachment

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Answer 2

Answer:

The second law of motion states that rate of change of momentum of an object is proportional to the applied force.

Derivation:

Let initial and final momentum of the object are p

1 =mu and p 2 =mv respectively.

The change in momentum p=mv−mup n m×(v−u)

The rate of change of momentum is directly proportional to applied force F

i.e., F∞

tm(v−u)F=k tm(v−u)

F=k.m.a

The unit of force is so chosen that the value of the constant, k becomes one.

For this, one unit of force is defined as the amount that produced an acceleration of 1 ms −2

In an object of 1 kg mass. That is,

1 unit of force =k×(1 kg)×(1 m s)

Thus, the value of k becomes 1.

So we can write

F=ma

or

a= mF

v=u+at

0=10

3 −10

7 t10 7 t=10 3

t= 10 710 3

=10 −4 s

Explanation:

Refer to the attachment.