A cube of side 0.2 m rests on the floor, as
shown. Given that the cube has a mass of 50 kg, the pressure exerted by the cube on the floor is
A-25 NM-²
B-250 NM-²
C-1250 NM-²
D-12500 NM-²
Answers
Answer:
Given :-
- A cube of side 0.2 m rests on the floor, as shown.
- The cube has a mass of 50 kg.
To Find :-
- What is the pressure exerted by the cube on the floor.
Formula Used :-
Force Formula :
where,
- F = Force
- m = Mass
- g = Acceleration due to gravity
Area Of Square Formula :
Pressure Formula :
where,
- P = Pressure
- F = Force
- A = Area Of Surface
Solution :-
First, we have to find the force :
Given :
- Mass (m) = 50 kg
- Acceleration due to gravity (g) = 10 N/kg or m/s²
According to the question by using the formula we get,
Hence, the force is 500 N .
Now, we have to find area of surface :
Given :
- Side = 0.2 m
According to the question by using the formula we get,
So, area of surface will be :
Now, we have to find the pressure exerted by the cube on the floor :
Given :
- Force (F) = 500 N
- Area of Surface (A) = 0.04 m²
According to the question by using the formula we get,
Hence, the correct options is option no (D) 12500 N/m² .
Answer:
- 12500 Pascal is the required answer.
Step-by-step explanation:
According to the Question
It is given that,
- Acceleration due to gravity ,g = 10m/s²
- Mass ,m = 50kg
- Side of cube = 0.2 m
we have to calculate the pressure exerted by the cube on the floor .
As we know that Pressure is defined as the force acting per unit area.
- Pressure = Force/Area
→ Pressure = mg/area
On substituting the value we get
→ Pressure = 50×10/0.2 × 0.2
→ Pressure = 500/0.04
→ Pressure = 50000/4
→ Pressure = 12500 Pa
- Hence, the pressure exerted by the cube on the floor is 12500 Pascal.