Math, asked by AnanyaBaalveer, 16 days ago


\large \red{\sf{Question}}
Shally buys some chocolates at the rate of 10 per chocolate. She also buys an equal number of candies at the rate of R 5 per candy. She makes 20% profit on chocolates and 8% profit on candies. At the end of the day, al chocolates and candies are sold out and her profit is F 240. The number of chocolates she had purchased is
(1) 100
(2) 90
(3) 150
(4) 200​

Answers

Answered by arshpreetsingh2975
1

a)100

I hope this will help you

Answered by talpadadilip417
1

Step-by-step explanation:

Correct Option Is (A)100

Solution:-

Let Kusum purchased x chocolates.

Then, total cost of chocolates =10 x

Similarly. she purchased x candies.

Then, total cost of candies =5 x

According to the question,

Profit on chocolates

 \text{ \( \rm=20  \%  \) of \(  \rm10 x=\dfrac{20}{100} \times 10 x \) \( \rm =2 x \)}

and profit on candies

 \text{\( \rm =8 \% \) of \( \rm 5 x=\dfrac{8}{100} \times 5 x=0.4 x \)}

 \text{ \( \therefore \quad \) Total profit \( \rm =2 x+0.4 x=24 x \)}

Again, according to the question,

\pmb{\text{Total profit \(\bf =240 \Rightarrow 24 x=240 \Rightarrow x=100 \)}}

Hence, she purchased 100 chocolates.

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